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The circle below is centered at the point (3, 1) and has a radius of length 2.
What is its equation?
O A. (x-3)2+(8-1)2 =
(x + 1)2 + (y+ 3)2 =
O C. (x+3)2+(+12
-
10
O
D. (x-1)2 + (y- 3)2 = 4

Respuesta :

bhuvna789456

Equation of the circle is (x - 3)² + (y - 1)² = 4

Step-by-step explanation:

  • Step 1: Given the center of circle (h,k) = (3,1) and radius, r = 2

Equation of the circle = (x-h)² + (y-k)² = r²

⇒ (x - 3)² + (y - 1)² = 4

⇒ x² - 6x + 9 + y² - 2y + 1 = 4

⇒ x² + y² - 6x - 2y + 6 = 0 (on simplification)

kanurashidatu

Answer:

(x-1)2 + (y- 3)2 = 2^2

Step-by-step explanation:

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