Laura2611
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There is a pole in a lake.54 feet of the pole is in mud below the water, 1/2 of it is covered by water, and 36 feet are out of the water.
PART A
If 20% of the pole is out of the water, what is the length of the pole
PART B
What percent of the pole is in the mud below the water? Explain.

Respuesta :

numbrain
A. 180' you do 100÷20=5 then do 36•5=180

B. 30% 54÷180•100=30

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