Respuesta :

1/x+x/(x+2)=1

take LCM
[tex](x+2)+x^2/(x(x+2)=1[/tex]
x+2+x^2=x(x+2)
[tex]x^2+x+2=x^2+2x[/tex]
x=2
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2)[tex]1/(x-3)+1/(x+5)=x+1/x-3[/tex]

[tex]x+5+x-3/(x+1)(x-3)=x+1/x-3[/tex]
[tex]2x+2=(x+1)(x+5) [/tex]
[tex]2x+2=x^2+5x+x+5[/tex]
[tex]x^2+4x+3=0[/tex]
[tex]x^2+3x+x+3=0[/tex]
(x+1)(x+3)=0
x= - 1, x= - 3

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3)[tex]3x/x^2+2x-8=1/x-2+x/x+4[/tex]

after solving both side u will get

[tex]3x=x+4+x-2[/tex]
3x=2x+2
x=2

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[tex]1/x^2-1 =2/x^2+x-2[/tex]

1/(x-1)(x+1)=2/(x-1)(x+2)
u will get same will cross out each other
1/(x+1)=2/(x+2)
(x+2)=2(x+1)
x+2=2x+2
x=0

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