we have the formula with the delta for [tex]a {x}^{2} + bx + c = 0[/tex] the delta is [tex] {b}^{2} - 4ac = {29}^{2} - 4.1.100 \\ = 441 = {21}^{2} [/tex] x [tex]x = ( - 29 + 21) \div 2 = - 4 \\ x = ( - 29 - 21 \div 2 = - 25[/tex] and these are two solutions
