Respuesta :

backseatdog
Use the rational roots test.  The possible roots are: plus/minus 6,3,2,1

Use synthetic division and you will see that 3 is a root:

3 | 1 -3 -3 11 -6
   |    3  0  -9  6
   ____________
     1 0  -3   2 0

Use rational root again, to see that possible roots are: plus/minus 2,1

Try 2:

2 | 1 0 -3 -2
   |    2  4  2       
   _____________
     1  2  1  0

The above is x^2+2x+1 which is a perfect square: (x+1)^2

So we have the final factorization: (x-3)(x-2)(x+1)^2

So the roots are: 3, 2, -1
Where -1 is a double zero.

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