A rectangular photograph is mounted on a poster and has a two inch border on each side. The poster itself is mounted on a frame whose sides are the same length as the sides of the poster. The frame cost $2 per inch and the cost of the frame was $160. If the area of the photograph is 231 inches squared. What are the dimensions of the frame?
Let's define variables: w: width of the photograph l: length of the photograph The cost of the box is: 2 * (2 * (w + 2)) + 2 * (2 * (l + 2)) = 160 The area is: (w + 2) * (l + 2) = 231 Solving the system of equations we have: w = 5 inches l = 31 inches Then, the dimensions of the frame are: w + 2 = 7 inches l + 2 = 33 inches Answer: the dimensions of the frame are: 7 inches * 33 inches
